In Bash, you can return values from functions using the return
statement. The return
statement allows you to specify an exit status or a value that will be available to the caller of the function. Here’s an example:
#!/bin/bash
add_numbers() {
local sum=$(( $1 + $2 ))
return $sum
}
# Calling the function and capturing the return value
add_numbers 5 3
result=$?
echo "Sum: $result"
In this example, the add_numbers
function takes two arguments, 5
and 3
, and calculates their sum. The local
keyword is used to declare a local variable sum
within the function, which holds the calculated sum. The return
statement is used to return the value of sum
.
When the function is called with add_numbers 5 3
, the return $sum
statement will set the exit status of the function to the value of sum
, which is 8
in this case. The return value can be accessed using the special variable $?
.
The next line of code captures the return value of the function in the variable result
. Finally, the script prints the value of result
, which gives the sum:
Sum: 8
By using the return
statement, you can pass values from a function back to the calling code. This allows you to perform calculations or tasks within the function and retrieve the results in the main script for further processing.